Question

If R1=5 R2=10 R3=15 and the potential difference is 6v in second circuit. What is the
current present in it.​

Answer 1

Answer:

Current present in the circuit is 0.2 Ampere.

Explanation:

Given :-

Resistance = 5Ω + 10Ω + 15Ω = 30Ω

Potential difference = 6 V

To find :-

Current

Solution :-

From Ohm's law,

• $V = IR$

• $6 = I*30$

• $I = \frac{V}{R}$

• $I = \frac{6}{30}$

• $I = 0.2 A$

∴ Current present in the circuit is 0.2 Ampere.

Answer 2

Answer:

The equivalent resistance of the 5Ω, 10Ω, 30Ω resistors connected in parallel is

R

p

1

=

5

1

+

10

1

+

30

1

=

30

6+3+1

=

30

10

∴R

p

=3Ω

∴, the total resistance of the given circuit is 3 Ohms.

The total current can be calculated using the Ohm's law as the value of voltage (V) is already given.

using Ohm's law

Voltage=Current×Resistance

⇒I=

R

V

=

3

12

=4A

Current through each resistor can be calculated by applying Ohm's law given that the voltage of the circuit and the individual resistances of each resistor is already given.

Current through 5Ω resistor =

R

V

=

5

12

=2.4A

Current through 10Ω resistor =

R

V

=

10

12

=1.2A

Current through 30Ω resistor =

R

V

=

30

12

=0.4A

Explanation:

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