Physics, asked by haseenaakbar75, 6 months ago

If R1=5ohm R2=10 Ohm and R3= 15 ohm are connected in two different arrangements as shown. (i) Find the current flowing in each of the circuit. (ii) ratio of current flowing. If the arrangements are connected to a 12v battery

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Answers

Answered by pratik7086
1
In first circuit
Equivalent resistance of R1 and R2 is 15
And the equivalent resistance of the whole circuit is = 15*15/15+15=15/2 ohm
And the current through the first circuit is
I= V/R=12*2/15=1.6 amp

In second circuit
Equivalent resistance of R2 and R3 is 10+15=25 ohm
The equivalent resistance of the whole circuit is 25*5/25+5=25/6
Current I = 12*6/25=2.88=2.9


Ratio:
1.6:2.9
16:29
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