Question

If R1 = 5ohm, R2 = 8ohm, R3 = 12 ohm and a 6 V battery is connected to the series arrangement. Calculate (a) the total resistance in the circuit and (b) the total current flowing in the circuit (c) voltage across 12 ohm

Answer 1

Answer:

Resistance in series R1+R2+R3=5+8+12=25Ω

acc. to ohms law I=V/R=6/25=0.25 A

and voltage V=IR= 0.25×12=3V

Answer 2

Answer:

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