Question

If R1 and R2 be the resistance of the filament of 40 W and 60 W respectively operating 220 V, then

Answer 1

Given that,

Power of R₁ = 40 W

Power of R₂ = 60 W

Voltage = 220 V

We need to calculate the value of resistance R₁

Using formula of power

$P=\dfrac{V^2}{R_{1}}$

Where, P = power

V = voltage

R = resistance

$40=\dfrac{220^2}{R_{1}}$

$R_{1}=\dfrac{220^2}{40}$

$R_{1}=1210\ \Omega$

We need to calculate the value of resistance R₂

Using formula of power

$P=\dfrac{V^2}{R_{2}}$

Put the value into the formula

$60=\dfrac{(220)^2}{R_{2}}$

$R_{2}=\dfrac{220^2}{60}$

$R_{2}=806.6\ \Omega$

Hence, The value of resistance R₂ and R₁  are 1210 Ω and 806.6 Ω

Answer 2

Answer:

Explanation:

Given that,

Power of R₁ = 40 W

Power of R₂ = 60 W

Voltage = 220 V

We need to calculate the value of resistance R₁

Using formula of power

Where, P = power

V = voltage

R = resistance

We need to calculate the value of resistance R₂

Using formula of power

Put the value into the formula

Hence, The value of resistance R₂ and R₁  are 1210 Ω and 806.6 Ω