If R1 is 20 ohm and R2 is 40 ohm,what is the current flowing in the circuit if the two resistors are connected in series. The battery connected is 6.0V?
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R=r1+r2=20+40=60 ohm
v=6 volt
i= R/v
=60/6= 10 amp
v=6 volt
i= R/v
=60/6= 10 amp
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