Question

If r1 is the radius of the first orbit of hydrogen atom, then the radii of second, third and fourth orbits in term of r1 are ???

Answer 1

Explanation:

And respectively it will follow

Answer 2

Answer:

The radii of second, third and fourth orbits in term of first orbit is:

$r_2=4\times r_1$

$r_3=9\times r_1$

$r_4=16\times r_1$

Explanation:

Formula used for the radius of the $n^{th}$ orbit will be,

$r_n=\frac{n^2\times 52.9}{Z}$   (in pm)

where,

$r_n$ = radius of $n^{th}$ orbit

n = number of orbit

Z = atomic number

Radius of first orbit, n=1

$r_1=\frac{1^2\times 52.9}{1}=52.9 pm$ ..(1)

Radius of second orbit, n=2

$r_2=\frac{2^2\times 52.9}{1}$

$r_2=4\times r_1$ (from(1))

Radius of third orbit, n=3

$r_3=\frac{3^2\times 52.9}{1}$

$r_3=9\times r_1$ (from(1))

Radius of forth orbit, n=4

$r_4=\frac{4^2\times 52.9}{1}$

$r_4=16\times r_1$ (from(1))