if r1,r2,r3 are root of polynomial 7x³+21x²7x³+21x²-4x+6 then
Answers
Answered by
1
Answer:
Correct option is
C
19
We know that A.M≥G.M
4
2
r
1
+
4
r
2
+
5
r
3
+
8
r
4
≥(
2
r
1
4
r
2
5
r
3
8
r
4
)
4
1
We know from the given equation that (r
1
r
2
r
3
r
4
)=
4
5
Substituting we get.
G.M.=(
64⋅(4)
1
)
4
1
=
4
1
Hence, A.M=G.M(∵
2
r
1
+
4
r
2
+
5
r
3
+
8
r
4
=1)
∴ The numbers will be equal.
2
r
1
=
4
r
2
=
5
r
3
=
8
r
4
=
4
1
Hence,
r
1
=
2
1
,r
2
=1,r
3
=
4
5
,r
4
=2→(1)
From the equation given , we get sum of the roots as
r
1
+r
2
+r
3
+r
4
=
4
a
→(2)
From (1) and (2), we get
4
19
=
4
a
⇒a=19
Step-by-step explanation:
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Answered by
0
Answer:
if r1,r2,r3 are root of polynomial 7x³+21x²7x³+21x²-4x+6 then
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