If r1=r2=r3=r4=r5=4 ohm find the equivalent resistance of( rs ) of the circuit
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Answer:R2 & R3 are in series so R23 = 4 + 4 = 8 Ω
R23 is parallel to R4, so R234 :-
1/R234 = 1/8 + 1/4
1/R234 = 0.125 + 0.25
R234 = 2.67 Ω
R1 , R5 and R234 in series, so equivalent resistance R' = 4 + 4 + 2.67 = 10.67 Ω
Equivalent resistance = 10.67 Ω
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