Math, asked by vidyasrivsoujt, 1 year ago

If radha were younger by 5 years then what she really is,then square of age would have 11 more than 5 times her actual age.What is her age now.

Answers

Answered by aryastark
1
Let her present age be x.

According to the first statement, if Radha had been younger by five years, her age would have been (x-5) yrs.

So,
(x-5)²= 5x -11

x²+ 25 -10x = 5x-11 [ using identity (a-b)²= a²+b²-2ab ]

x²-15x + 36= 0

x² -3x -12x +36= 0 [ solving the quadratic equation using middle term splitting method ]

x(x-3)-12(x-3)= 0

(x-3)(x-12)=0

Therefore, on solving the equation we get two answers ie 3 and 12, but her age can not be 3 years because if it were so, then she could not have talked about her age 5 years before.

Hence, her present age is 12 years.
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