If radiations of 5*10^10 Hz frequency are emitted from a 440 W bulb then calculate the number of photons emitted per minute
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electrical energy supplied in one sec = 60 J
(as power = 60 W)
10% of this energy =60×
100
10
=6J
Only 6J of energy is converted to light energy
energy of each proton =
λ
hc
=
A
hc
=
6000×10
−10
6.626×10
−34
×3×10
8
=3.313×10
−19
J
No. of photons =
energyofphoto
energy/persec
=
3.313×10
−19
6
=1.8×10
−19
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