Question

If radii of frustum are 5 and 3 cm ,h=9cm then volume of frustum of the cone is

Answer 1

Step-by-step explanation:

Here,h=9cm

r1=5cm

r2=3cm.

Volume of a frustum

=1/3× pai ×h ×(r1^2+r2^2+r1×r2)

=1/3×22/7×9×(5^2+3^2+5×3)

=22/7×3(25+9+15)

=22/7×3×49

=22×3×7

=462 cu cm.