Question

if radius and height of cone both are increased by 10%, then volume of the cone is increased by

Answer 1

Volume = V = πr^2h/3
r' = r+(10/100)r
r' = (11/10)r
h' = (11/10)h

New Volume = V' = πr'^2h'
= π× {(11/10)r}^2 × (11/10)h
= πr^2h × (1331/1000)

V' = (1331/1000)V

% change = {(1331/1000)V-V}/V × 100
= (331/1000) × 100
= 33.1 % increase
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