Question

If radius is halved and the height is one-third of its original. What will be the percentage change in the volume? Please hurry

Answer 1

VOLUME OF CONE=$\frac{\pi r^{2}h }{3}$

Step-by-step explanation:

[tex]V_{2} =\frac{\pi (R/2)^{2} (H/3)}{3} \\ V_{2} =\frac{\pi R^{2}H }{4*3*3} \\ V_{2}=V_{1}/12\\ [/tex]

Percentage change in volume=[tex] \frac{v_{1}- v_{2}}{v_{1} } =\frac{12v_{1}-v_{1} }{12v_{1} } \\ =\frac{11}{12} *100=91.67[/tex]