if radius OD is perpendicular to chord AB at C, AC = 2(6.5-x), AB = 15, find x
Answers
Answered by
3
Because the radius is perpendicular to the cord AC is half of AB
Then,
∴ AB = 1/2 × 2 (6.5 - x)
∴ 15 = 1/2 × 13 - 2x
∴ 15 = 6.5 - 2x
∴ 15 + 2x = 6.5
∴ 2x = 6.5 - 15
∴ x = -8.5/2
∴ x = - 4.25
X = - 4.25
▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃
Similar questions