If radius of a cylinder is doubled and height is halved then show that the volume will be doubled
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Old volume = πr^2h
new volume = π(2r)^2(h/2)
π(4r^2)(h/2)
= 4πr^2h/2
= 2πr^2h
Hence, we shown that the volume is doubled
new volume = π(2r)^2(h/2)
π(4r^2)(h/2)
= 4πr^2h/2
= 2πr^2h
Hence, we shown that the volume is doubled
Lordritesh:
thnx
welcome....bro.
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