If radius of a sphere is doubled then how many times of its volume is increased
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Answer:
New volume = 8 times earlier volume
Step-by-step explanation:
Original volume = 4/3 * 22/7 * r^3(i)
Now r'=2r
New Volume = 4/3 * 22/7 * (r')^3
New Volume = 4/3 * 22/7 * 8r^3 (ii)
Dividing i by ii-> Org. Vol/New Vol. = 1/8
New volume will become 8 times the earlier volume
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