If radius of curvature of a concave mirror is 20cm and an object of height 3 cm is placed
at 30cm from the mirror. Find position, nature and size of the image?
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Answer:
position = image will be formed at the distance of 15 cm on the side of the object.
nature= 1.Real
2. highly diminished
size = 1.5 cm
Explanation:
height of object =3cm
radius of curvature = 20 cm
distance of object placed (u) =30 cm
now
we know that focal length = 2×radius of curvature
Therefore, focal length (f)= 10cm
now
by mirror formula = 1/f=1/v+1/u
= -1/10=1/v+(-1/30) ( minus is because it is placed on the right side of the mirror)
= v=-15cm
(IT MEANS THAT IMAGE IS ALSO FORMED ON THE RIGHT SIDE OF YHE MIRROR)
now
magnification =v/u=15/30=1/2
now
m=image size/object size
1/2=image size/3
image size =1.5 cm.
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