Question

If radius of earth is 6400km and mass 10^31kg. Find Moment of Inertia of Earth rotating about its own axis ​

Answer 1

Answer:

Given radius of the earth is 6400 km

velocity of a point on the equator is

v=

24

2πR

km/hr (since the point covers 1 full rotation in 24 hrs)

acceleration of the equator point is

a=v

2

/R

a=6400

2

×

6400×576

4π

2

km/hr

2

a=3.4 cm/s

2