Question

if radius of earth is R and if time taken for earth to complete one revolution about its own axis T then acceleration of particle placed on surface of earth at equater due to earth rotation will be​

Answer 1

Answer:

$\frac{4\pi^2R}{T}^2$

Explanation:

Radius of the Earth = R

Time period = T

The angular velocity of the Earth

$\omega=\frac{2\pi}{T}$

The acceleration of the particle at the equator due to earth's rotation

$=\omega^2R$

$=(\frac{2\pi}{T})^2R$

$=\frac{4\pi^2R}{T}^2$

Hope this is helpful.