Question

if radius of ends of a bucket are 5cm and 15cm and it is 24 cm height then it's surface area is​

Answer 1

Answer:

2420 cm^2

Step-by-step explanation:

Since the bucket is in shape of a frustum we get,

R1=5 cm

R2=15 cm

H=24 cm

Slant height of cone=√(R1-R2)² +H²=26 cm

Surface area=π(R1+R2)l +πR1²+πR2²

                     =π[520+25+225]

                     =22/7××770

                    =2420 cm²

Answer 2

The surface area is 1632.8 cm².

Step-by-step explanation:

Given : If radius of ends of a bucket are 5 cm and 15 cm and it is 24 cm height.

To find : The surface area of bucket ?

Solution :

The bucket is in shape of a frustum,

where, the radius are $r_1=5\ cm$ and $r_2=15\ cm$

The height is h=24 cm

The slant height is given by,

$l=\sqrt{(r_2-r_1)^2+h^2}$

$l=\sqrt{(15-5)^2+24^2}$

$l=\sqrt{100+576}$

$l=\sqrt{676}$

$l=26\ cm$

The surface area of the bucket is given by,

$SA=\pi(r_1+r_2)l$

$SA=3.14\times (15+5)26$

$SA=3.14\times (20)26$

$SA=3.14\times520$

$SA=1632.8$

The surface area is 1632.8 cm².

#Learn more

The radii of the circular ends of a solid frustum of a cone are 18 cm and 12 cm and its height is 8 cm. find its total surface area

https://brainly.in/question/6974186