If radius of second excited state of he+ is x cm .the radius of first excited state of li+2 is
Answers
Answer:
As we know,
As we know,r
As we know,r n
As we know,r n
As we know,r n =
As we know,r n = Z
As we know,r n = Zr
As we know,r n = Zr 1
As we know,r n = Zr 1
As we know,r n = Zr 1 forH×n
As we know,r n = Zr 1 forH×n 2
As we know,r n = Zr 1 forH×n 2
As we know,r n = Zr 1 forH×n 2
As we know,r n = Zr 1 forH×n 2 =
As we know,r n = Zr 1 forH×n 2 = Z
As we know,r n = Zr 1 forH×n 2 = Z0.529A×n
As we know,r n = Zr 1 forH×n 2 = Z0.529A×n 2
As we know,r n = Zr 1 forH×n 2 = Z0.529A×n 2
As we know,r n = Zr 1 forH×n 2 = Z0.529A×n 2
As we know,r n = Zr 1 forH×n 2 = Z0.529A×n 2
As we know,r n = Zr 1 forH×n 2 = Z0.529A×n 2 r
As we know,r n = Zr 1 forH×n 2 = Z0.529A×n 2 r 2
As we know,r n = Zr 1 forH×n 2 = Z0.529A×n 2 r 2
As we know,r n = Zr 1 forH×n 2 = Z0.529A×n 2 r 2 for Li
As we know,r n = Zr 1 forH×n 2 = Z0.529A×n 2 r 2 for Li 2+
As we know,r n = Zr 1 forH×n 2 = Z0.529A×n 2 r 2 for Li 2+ =
As we know,r n = Zr 1 forH×n 2 = Z0.529A×n 2 r 2 for Li 2+ = 3
As we know,r n = Zr 1 forH×n 2 = Z0.529A×n 2 r 2 for Li 2+ = 30.529A×2
As we know,r n = Zr 1 forH×n 2 = Z0.529A×n 2 r 2 for Li 2+ = 30.529A×2 2
As we know,r n = Zr 1 forH×n 2 = Z0.529A×n 2 r 2 for Li 2+ = 30.529A×2 2
As we know,r n = Zr 1 forH×n 2 = Z0.529A×n 2 r 2 for Li 2+ = 30.529A×2 2
As we know,r n = Zr 1 forH×n 2 = Z0.529A×n 2 r 2 for Li 2+ = 30.529A×2 2 =
As we know,r n = Zr 1 forH×n 2 = Z0.529A×n 2 r 2 for Li 2+ = 30.529A×2 2 = 3
As we know,r n = Zr 1 forH×n 2 = Z0.529A×n 2 r 2 for Li 2+ = 30.529A×2 2 = 30.529A×4
As we know,r n = Zr 1 forH×n 2 = Z0.529A×n 2 r 2 for Li 2+ = 30.529A×2 2 = 30.529A×4
As we know,r n = Zr 1 forH×n 2 = Z0.529A×n 2 r 2 for Li 2+ = 30.529A×2 2 = 30.529A×4 A
As we know,r n = Zr 1 forH×n 2 = Z0.529A×n 2 r 2 for Li 2+ = 30.529A×2 2 = 30.529A×4 A 0
Explanation:
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