Question

If radius of second excited state of he+ is x cm .the radius of first excited state of li+2 is​

Answer 1

Answer:

As we know,

As we know,r

As we know,r n

As we know,r n

As we know,r n =

As we know,r n = Z

As we know,r n = Zr

As we know,r n = Zr 1

As we know,r n = Zr 1

As we know,r n = Zr 1 forH×n

As we know,r n = Zr 1 forH×n 2

As we know,r n = Zr 1 forH×n 2

As we know,r n = Zr 1 forH×n 2

As we know,r n = Zr 1 forH×n 2 =

As we know,r n = Zr 1 forH×n 2 = Z

As we know,r n = Zr 1 forH×n 2 = Z0.529A×n

As we know,r n = Zr 1 forH×n 2 = Z0.529A×n 2

As we know,r n = Zr 1 forH×n 2 = Z0.529A×n 2

As we know,r n = Zr 1 forH×n 2 = Z0.529A×n 2

As we know,r n = Zr 1 forH×n 2 = Z0.529A×n 2

As we know,r n = Zr 1 forH×n 2 = Z0.529A×n 2 r

As we know,r n = Zr 1 forH×n 2 = Z0.529A×n 2 r 2

As we know,r n = Zr 1 forH×n 2 = Z0.529A×n 2 r 2

As we know,r n = Zr 1 forH×n 2 = Z0.529A×n 2 r 2 for Li

As we know,r n = Zr 1 forH×n 2 = Z0.529A×n 2 r 2 for Li 2+

As we know,r n = Zr 1 forH×n 2 = Z0.529A×n 2 r 2 for Li 2+ =

As we know,r n = Zr 1 forH×n 2 = Z0.529A×n 2 r 2 for Li 2+ = 3

As we know,r n = Zr 1 forH×n 2 = Z0.529A×n 2 r 2 for Li 2+ = 30.529A×2

As we know,r n = Zr 1 forH×n 2 = Z0.529A×n 2 r 2 for Li 2+ = 30.529A×2 2

As we know,r n = Zr 1 forH×n 2 = Z0.529A×n 2 r 2 for Li 2+ = 30.529A×2 2

As we know,r n = Zr 1 forH×n 2 = Z0.529A×n 2 r 2 for Li 2+ = 30.529A×2 2

As we know,r n = Zr 1 forH×n 2 = Z0.529A×n 2 r 2 for Li 2+ = 30.529A×2 2 =

As we know,r n = Zr 1 forH×n 2 = Z0.529A×n 2 r 2 for Li 2+ = 30.529A×2 2 = 3

As we know,r n = Zr 1 forH×n 2 = Z0.529A×n 2 r 2 for Li 2+ = 30.529A×2 2 = 30.529A×4

As we know,r n = Zr 1 forH×n 2 = Z0.529A×n 2 r 2 for Li 2+ = 30.529A×2 2 = 30.529A×4

As we know,r n = Zr 1 forH×n 2 = Z0.529A×n 2 r 2 for Li 2+ = 30.529A×2 2 = 30.529A×4 A

As we know,r n = Zr 1 forH×n 2 = Z0.529A×n 2 r 2 for Li 2+ = 30.529A×2 2 = 30.529A×4 A 0

Explanation:

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