Question

If radius of the base of cylinder is 7cm and its height is 60cm, find
(i) Curved surface area of the cylinder.
(ii) Total surface area of the cylinder.​

Answer 1

Step-by-step explanation:

(i)

$curved \: surface \: area \: of \: cylinder = 2\pi rh$

$= 2 \times \frac{22}{7} \times 7 \times 60$

$= 2 \times 22 \times 1 \times 60$

$= 44 \times 60 = 2640 \: {cm}^{2}$

(ii)

$total \: surface \: area \: of \: cylinder = 2\pi r(r + h)$

$= 2 \times \frac{22}{7} \times 7 \times (7 + 60)$

$= 2 \times 22 \times 1 \times 67$

$= 44 \times 67 = 2948 \: {cm}^{2}$

Answer 2

Step-by-step explanation:

(i) curved surface area of cylinder = 2 x pi x r x h

=> pi = 22/7

= 2 x 22/7 x 7 x 60

= 2 x 22 x 60

= 44 x 60

= 2640 Sq.cm

(ii) Total surface area of cylinder = 2 x pi x r ( r+h)

= 2 x 22/7 x 7 ( 7+60)

= 2 x 22/7 x 7 ( 67 )

= 2 x 22 x 67

= 44 x 67

= 2948 Sq.cm

Hope this answer will help you.