Question

If rahul completes 3 rounds of a square track of side 6m each in 2 and a half minutes, find his speed and velocity.
pls answer { with explanation }
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Answer 1

Answer:

Speed = 0.48m/s and Velocity = 0m/s

Step-by-step explanation:

Given,

Side of square field = 6m

No. of rounds = 3

Time = 2.5 minutes = 120 + 30 seconds = 150 seconds.

As we know,

Perimeter of a square = 4*side

Perimeter of square field = 4*6m

Perimeter of square field = 24m

Distance covered by Rahul = 3(Perimeter of field)

Distance covered by Rahul = 3(24m)

Distance covered by Rahul = 72m

Time taken = 150 seconds.

We know that,

Speed = Distance/Time

Speed = 72m/150s

Speed = 0.48m/s

Now,

After 2.5 minutes he complete 3 rounds of field, so his displacement becomes zero.

Also,

Velocity = Displacement/Time

Velocity = 0m/150s

Velocity = 0m/s

Hence, the speed and velocity of Rahul is 0.48m/s and 0m/s respectively.

Hope it helps......