Question

If rahul completes 3 rounds of a square track of side 6m each in 2 and a half minutes, find his speed and velocity.

answer with explanation pls

Answer 1

GIVEN...

• number of rounds =3
• time taken=2.5 minutes
• length of one side of square track=6m

TO FIND...

1. speed
2. velocity

FORMULA USED...

• speed = Distance / Time
• velocity = Displacement / Time

CALCULATION...

1. Speed.

$perimeter \: of \: square \: = \: 4 \times side \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 4 \times 6 \: m \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 24 \: m \\ \\ total \: distance \: = 24 \: m \times 3 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 72 \: m \\ \\ time = 2.5 \: minutes \\ \: \: \: \: \: \: \: \: \: \: = (60 \: s \times 2) + 30 \: s \\ \: \: \: \: \: \: \: \: \: \: = 150 \: s \\ \\ speed = \frac{distance}{time} \\ \\ \: \: \: \: \: \: \: \: \: \: \: = \frac{72 \: m}{150 \: s} \\ \\ \: \: \: \: \: \: \: \: \: \: \: = 0.48 \: m \: s ^{ - 1}$

2. Velocity

$here \: rahul \: completed \: 3 \: rounds \\ \: of \: the \: square \: track \: so \: his \: total \: \\ displacement \: becomes \: 0 \: m. \\ \\ \: \: \: \: velocity = \frac{displacement}{time} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{0 \: m}{150 \: s} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 0 \: m \: s ^{ - 1}$

Therefore, the speed and velocity of Rahul are 0.48 m/s and 0 m/s respectively.