Question

*If Raj went 24 m to the north and 32 m to the east from the same place on the ground, what would be the minimum distance between the two points ?*

1️⃣ 56 m
2️⃣ 40 m
3️⃣ 36 m
4️⃣ 45 m
*I want quick help please help​

Answer 1

Question :

If Raj went 24 m to the north and 32 m to the east from the same place on the ground, what would be the minimum distance between the two points ?*

Answer :

• Let A be Raj's starring point .

• let B be Raj's ending point .

• The path covered by Raj is passing through A , C and B that is distance of AC + CB

• But the minimum distance between the starting and ending point will be the seg AB .

We can find it through the Pythagoras theorem .

Here , triangle ∆ACB is formed ,

By Pythagoras theorem

hypo² = base² + opposite ²

➡️ AB² = AC² + BC²

➡️ AB² = 24² + 32²

➡️ AB² = 576 + 1024

➡️ AB² = 1600

➡️ AB = √1600

➡️ AB = 40

Therefore the minimum distance between the starting and ending point is 40 m .

Answer 2

Given : Raj went 24 m to the north and 32 m to the east from the same place on the ground,

To Find : the minimum distance between the two points

1️⃣ 56 m

2️⃣ 40 m

3️⃣ 36 m

4️⃣ 45 m

Solution:

            NORTH

WEST                 EAST

             SOUTH

North and west are perpendicular

Apply Pythagoras' theorem: square on the hypotenuse of a right-angled triangle is equal to the sum of the squares of the other two perpendicular sides.

Distance = √24² + 32²

= 8√3² + 4²

= 8√(9 + 16)

= 8√25

= 8(5)

= 40 m

distance between the two points  = 40 m

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