Physics, asked by shivansh4458, 3 months ago

if rajiv throws a ball and it touches ground in 5 secons what is height of building​

Answers

Answered by debnathabhishek914
0

The general formula for this is:

The general formula for this is:Distance_2 = 1/2 * Acceleration * Time * Time + Initial Velocity * Time + Distance_1

The general formula for this is:Distance_2 = 1/2 * Acceleration * Time * Time + Initial Velocity * Time + Distance_1Since you didn’t mention an initial velocity, let’s assume that’s Zero (0).

The general formula for this is:Distance_2 = 1/2 * Acceleration * Time * Time + Initial Velocity * Time + Distance_1Since you didn’t mention an initial velocity, let’s assume that’s Zero (0).You asked for height above ground (Distance_1) and Distance_2 is Zero (0), height at ground.

The general formula for this is:Distance_2 = 1/2 * Acceleration * Time * Time + Initial Velocity * Time + Distance_1Since you didn’t mention an initial velocity, let’s assume that’s Zero (0).You asked for height above ground (Distance_1) and Distance_2 is Zero (0), height at ground.Acceleration due to gravity at sea level (assuming this is at sea level) is -9.8 meters/second/second. We represent this by g.

The general formula for this is:Distance_2 = 1/2 * Acceleration * Time * Time + Initial Velocity * Time + Distance_1Since you didn’t mention an initial velocity, let’s assume that’s Zero (0).You asked for height above ground (Distance_1) and Distance_2 is Zero (0), height at ground.Acceleration due to gravity at sea level (assuming this is at sea level) is -9.8 meters/second/second. We represent this by g.Filling in the Zeros and using H for height above ground, our new formula is:

The general formula for this is:Distance_2 = 1/2 * Acceleration * Time * Time + Initial Velocity * Time + Distance_1Since you didn’t mention an initial velocity, let’s assume that’s Zero (0).You asked for height above ground (Distance_1) and Distance_2 is Zero (0), height at ground.Acceleration due to gravity at sea level (assuming this is at sea level) is -9.8 meters/second/second. We represent this by g.Filling in the Zeros and using H for height above ground, our new formula is:0 = 1/2 * g * t^2 + 0 * t + H

The general formula for this is:Distance_2 = 1/2 * Acceleration * Time * Time + Initial Velocity * Time + Distance_1Since you didn’t mention an initial velocity, let’s assume that’s Zero (0).You asked for height above ground (Distance_1) and Distance_2 is Zero (0), height at ground.Acceleration due to gravity at sea level (assuming this is at sea level) is -9.8 meters/second/second. We represent this by g.Filling in the Zeros and using H for height above ground, our new formula is:0 = 1/2 * g * t^2 + 0 * t + HSimplifying and rewriting that, we get:

The general formula for this is:Distance_2 = 1/2 * Acceleration * Time * Time + Initial Velocity * Time + Distance_1Since you didn’t mention an initial velocity, let’s assume that’s Zero (0).You asked for height above ground (Distance_1) and Distance_2 is Zero (0), height at ground.Acceleration due to gravity at sea level (assuming this is at sea level) is -9.8 meters/second/second. We represent this by g.Filling in the Zeros and using H for height above ground, our new formula is:0 = 1/2 * g * t^2 + 0 * t + HSimplifying and rewriting that, we get:H = -1/2 * g * t^2

The general formula for this is:Distance_2 = 1/2 * Acceleration * Time * Time + Initial Velocity * Time + Distance_1Since you didn’t mention an initial velocity, let’s assume that’s Zero (0).You asked for height above ground (Distance_1) and Distance_2 is Zero (0), height at ground.Acceleration due to gravity at sea level (assuming this is at sea level) is -9.8 meters/second/second. We represent this by g.Filling in the Zeros and using H for height above ground, our new formula is:0 = 1/2 * g * t^2 + 0 * t + HSimplifying and rewriting that, we get:H = -1/2 * g * t^2t = 5 seconds

The general formula for this is:Distance_2 = 1/2 * Acceleration * Time * Time + Initial Velocity * Time + Distance_1Since you didn’t mention an initial velocity, let’s assume that’s Zero (0).You asked for height above ground (Distance_1) and Distance_2 is Zero (0), height at ground.Acceleration due to gravity at sea level (assuming this is at sea level) is -9.8 meters/second/second. We represent this by g.Filling in the Zeros and using H for height above ground, our new formula is:0 = 1/2 * g * t^2 + 0 * t + HSimplifying and rewriting that, we get:H = -1/2 * g * t^2t = 5 secondsg = -9.8 meters/second/second

Answered by vrindagandhi746
1

Explanation:

u= 0

a= g= 10 m/

t= 5 s

s = ut + 1/2at²

=1/2 *10*5²

s= 125 m ans

pls mark it as brainliest

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