if Ram walks from his house to School at the rate 3km/hr, he reaches 15 minute late lf he walks at 4 km/hr he reaches 15 minutes earlier than the scheduled time the distance between his house and School is
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Let distance between Ram’s school and his house is D km and actual time taken by Ram to reach his school from his home is ‘t’ minutes.
According to the question,
D = 3 × (t + 6)/60 ----(1)
And, D = 4 × (t - 4)/60 ----(2)
Equating equation (1) and (2), we get
3 × (t + 6)/60 = 4 × (t - 4)/60
⇒ 3t + 18 = 4t - 16
⇒ t = 34 minutes
∴ Distance (D) = 3 × (t + 6)/60 = 3 × (34 + 6)/60 = 2 km
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