Question

if Ramesh and suresh finish a work in 12 days.if suresh finishes that work in 20 days alone then in how many days Ramesh will finish that work alone?​

Answer 1

Answer:

Step-by-step explanation:

Given: suresh alone finish the work in 20 days

to find =days taken by ramesh to finish the work,so let ramesh did the work in

x days

SOLUTION:

so work done by suresh in one day =1/20

and work done by both of them in 1 day =1/12

so,work done by ramesh in one day =1/12-1/20

2/60

so total work done by ramesh in=30 days

Answer 2

Answer:

Ramesh will finish that work alone in 30 days.

Step-by-step explanation:

This is a problem of time and work.

By unitary method we can easily solve this.

Given,Ramesh and suresh finish a work in 12 days.Ramesh and Suresh in 1 day do work$\frac{1}{12}$part.

Now Suresh can do 1 work in 20 days.

So,Suresh in 1 day do work $\frac{1}{20}$part.

Now in 1 day Ramesh can do $= \frac{1}{12} - \frac{1}{20} = \frac{5 - 3}{60} = \frac{2}{60} = \frac{1}{30}$part work.

So Ramesh can do 1 work in 30 days.