Math, asked by anjana78, 11 months ago

if ramu have x rupees with him he gave 1 rupee to the begger and spent half of the money this countinous for six day at last he has no money how much money did have​

Answers

Answered by jarpana2003
1

Answer:

Step-by-step explanation:

He gives 1 rupee to beggar first and then spends half.

On 6th day, he had only 1 rupee.

Going from day 6 to day 1;

on 6th day, he had = Re 1

on 5th day, he had = 1×2 + 1 = 2+1 = Rs. 3

on 4th day, he had = 3×2 + 1 = 6+1 = Rs. 7

on 3rd day, he had = 7×2 + 1 = 14+1 = Rs. 15

on 2nd day, he had = 15×2 + 1 = 30+1 = Rs. 31

on 1st day, he had = 31×2 + 1 = 62+1 = Rs. 63

So he had Rs. 63 in the beginning.


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