Question

If rand s are the zeroes of the polynomial x2 - 6x + 8, the value of r²+s² is​

Answer 1

Answer:

= x^2 - 6x + 8

By splitting the middle term:= x^2 - 4x - 2x + 8

= x(x - 4) - 2(x - 4)

= (x - 4) (x - 2)

so by these we can say:

= x - 4 = 0

= x = 4

And;

= x - 2 = 0

= x = 2

therefore, r = 4 and s = 2

So,

= r^2 + s^2

= 4^2 + 2^2

= 16 + 4

= 20.

Hope this will help you...

Answer 2

QUESTION:-

If r and s are the zeroes of the polynomial ,  the value of r²+s² is​ ?

GIVEN:-

A polynomial

2 zeroes of the polynomial

TO FIND:-

The value of  r²+s²

EXPLANATION:-

If r and s are the zero then p(r) and p(s)=0

p(x)=x²-6x+8

p(x)=x²-6x+8

p(x)=x²-2x-4x+8

p(x)=x(x-4)-2(x-4)

p(x)=(x-4)(x-2)

P(x)=0

0=(x-4)(x-2)

x=2 and 4 so r=4 and s=2 and

r²+s² =4²+2²

r²+s²=16+4

r²+s²=20

LEARN MORE AT:-

(Q)-If one of the zero of the quadratic polynomial p(x)=x² + px + 1 is -3 then the value of p is ?

answer at =https://brainly.in/question/42771161