If ratio of partial pressure of substance A and B is P0
A
: P0
B
= 1 : 2 and ratio of molefraction is 1:2,
then calculate molefraction of A in vapour state ?
(A) 0.33 (B) 0.25 (C) 0.52 (D) 0.2
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Answer: option d
mole fraction of A in vapour phase=(P^0a*Xa)/(P^0 a*Xa +P^0b*Xb)
divide numerator and denominator with P^0 a *Xa
and equation becomes
mole fraction=1/(1+ P^0b*Xb/P^0a*Xa)
=1/1+4=0.2
Explanation:
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