Question

If ratio of sum of ages of A and B and difference of ages of A and B is 11:1.Than what is the ratio of five times age of A and thrice the age of B?​

Answer 1

Answer:

AGE OF A + AGE OF B = 11X.

AGE OF A - AGE OF B = X.

AGE OF A = 11X - AGE OF B.

AGE OF B = X - AGE OF A.

5 TIMES AGE OF A = 5(11X - AGE OF B)

3 TIMES AGE OF B = 3(X - AGE OF A)

RATIO OF AGE OF 5 TIMES AGE OF A TO 3 TIMES AGE OF B = 5(11X - AGE OF B)/3(X - AGE OF A).

55X - AGE OF B / 3X - AGE OF A

THEREFORE,

55X - B / 3X - A

55X - B : 3X - A

Answer 2

Answer:

AGE OF A + AGE OF B = 11X

AGE OF A - AGE OF B = X

AGE OF A = 11X- AGE OF B

AGE OF B = X - AGE OF A

5 TIMES AGE OF A = 5(11X-AGE OF B)

3 TIMES AGE OF B = 3(X-AGE OF A)

RATIO OF AGE OF 5 TIMES AGE OF A TO 3 TIMES AGE OF B =5(11X -AGE OF B) / 3(X - AGE OF A)

55X-AGE OF B / 3X - AGE OF A

THEREFORE,

55X - B / 3X - A

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