Question

if ratio of two no is 3:4 and their h.c.f is 4 find l.c.m

Answer 1

Let the two numbers be 3x and 4x.
Given H. C. F = 4
=> x = 4.
As we know that product of two numbers is equals to L. C. M × HCF,
=>3x × 4x = L. C. M x 4
=>L.C.M = 12x²/4
=>L. C. M = 48.

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Answer 2

Answer:

48

Step-by-step explanation:

x*y = LCM*HCF

3a*4a = LCM*4

LCM = 12$a^{2}$ / 4 = 3$a^{2}$

=> 3a*4a = 3$a^{2}$

=> 12a = 3$a^{2}$

=> a = 4

=> 3$a^{2}$

=> 3($4^{2}$)

=> 3*16

=> 48