If ray BD bisector of angle ABC and ray BE bisector of angle DBE ,If measure angle
EBC=20°, then find angle ABC.
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Step-by-step explanation:
Given AB=AC
In △ABC
BD is the bisector of ∠ABC
∴ by using angle bisector property we have
AD/DC = AB/BC .....(1)
and CE is the angle bisector of ∠ACB
∴ by using angle bisector property,
AE/EB = AD/BC....(2)
But segment AB=segment AC ......(3)
From (1),(2) and (3) we have
AE/EB = AD/DC
∴segment ED∥segment BC by converse of basic proportionality theorem.
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