Question

If, rcos theta= 2√3 and rsin theta = 2 .


r= ? and theta = ?

pls give me the answer fast

It is urgent .
friends.

………………………​

Answer 1

Answer:

here is your answer buddy.

Answer 2

Question :-

→ Given above ↑

Answer :-

$\to \boxed{\sf \theta \: = 30 \degree \: \: and \: r \: = {4}}$

To Find:-

$\sf \: find \: r \: and \: \: \theta$

Answer :-

We have ,

$\to \sf r \cos \theta = { 2 }{ \sqrt{3} } \: \: ....eq.(1) \\ \bf and \\ \to \sf \: r \sin \theta = 2 \: \: ....eq.(2)\\ \\ \sf squaring \: of \: both \: equations \: and \: then \\ \: \sf \: ading \: \\ \\ \to \sf {r}^{2} { \cos}^{2} \theta + {r}^{2} { \sin}^{2} \theta = 12 + 4 \\ \\ \to \sf {r}^{2} ( { \sin}^{2} \theta + { \cos}^{2} \theta) = {16} \\ \because \: { \sin}^{2} \theta + { \cos}^{2} \theta = 1 \\ \therefore \: \\ \to \sf {r}^{2} = {16} \\ \\ \to \boxed{ \sf \: r = 4 } \: \\ \\ \sf \: put \: in \: eq.(2) \\ \\ \to \: {4} \sin \theta = 2 \\ \\ \to \: \sin \theta = \frac{ 1}{2} \\ \\ \to \: \theta = { \sin}^{ - 1} ( \sin \: 30 \degree) \\ \\ \to \boxed{ \theta = 30 \degree \: }$