Chemistry, asked by Anonymous, 11 months ago

If reaction is second order how the rate of reaction affected if concentration is doubled and concentration is half.
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Answered by Anonymous

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Answered by arshbbcommander

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Let the concentration of the reactant be [A] = a

Rate of reaction, R = k [A]2 = ka2

(i) If the concentration of the reactant is doubled, i.e. [A] = 2a, then the rate of the reaction would be

R = k(2a)2

= 4ka2

= 4 R

Therefore, the rate of the reaction would increase by 4 times.

(ii) If the concentration of the reactant is reduced to half, i.e. [A] = 1/2 a,then the rate of the reaction would be

R = k(1/2a)2

= 1/4 Ka2

= 1/4 R

Therefore, the rate of the reaction would be reduced to ¼th

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...Hope it helps....

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