if reading of voltmeter in Ohm's law 4v and 6v for same current find the ratio of resistances
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Explanation:
potential difference for 1st=4V
" " """"""""" """ 2nd=6V
Let current =I
we know that,
Resistance for the 1st will be,
4V=IR (R is the resistance of the 1st)
R=4V/I
Now resistance for the 2nd will be,
6V=IR' (R' is the resistance of the 2nd)
R'=6V/I
Therefore the ratio of the radius will be,
R/R'=4V/I/6V/I
=4V/6V
=4/6
=2/3
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