Question

If real image formed by the concave mirror is twice the size of an object placed in front of it then what will be position of image from mirror

Answer 1

Explanation:

u=−30cm and magnification m=(−v/u)=−3 so v=(3u)

image is real so m should be negative v should be negative so v=−90cm

putting the above values of v and u in the Mirror equation,

f

1

=

u

1

+

v

1

we get focal length f=−22.5cm and image position v=−90cm

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Answer 2

Answer:

u=−30cm and magnification m=(−v/u)=−3 so v=(3u)

image is real so m should be negative v should be negative so v=−90cm

putting the above values of v and u in the Mirror equation,

f

1

=

u

1

+

v

1

we get focal length f=−22.5cm and image position v=−90cm

Explanation: