Math, asked by francislaciann, 1 year ago



If rectangle ABCD is dilated by a scale factor of 1.5 with a center of dilation at vertex A, how does the area of A'B'C'D' compare with the area of ABCD?
A) The area of A'B'C'D' is 3 times the area of ABCD.
B) The area of A'B'C'D' is 6 times the area of ABCD.
C) The area of A'B'C'D' is 1.5 times the area of ABCD.
D) The area of A'B'C'D' is 2.25 times the area of ABCD.

Answers

Answered by jalenjeannite
6

The Answer................  D


Answered by isyllus
2

Answer:

D is correct.  

The area of A'B'C'D' is 2.25 times the area of ABCD.

Step-by-step explanation:

If a rectangle ABCD is dilated by a scale factor of 1.5 with a center of dilation at vertex A.

Dilated rectangle is A'B'C'D'. Center of dilation is A.

Therefore, A=A'

Scale factor is 1.5

A'B'=1.5 AB

A'D'=1.5 AD

Area of rectangle ABCD = AB x AD

Area of rectangle A'B'C'D' = A'B' x A"D"

Area of rectangle A'B'C'D' = 1.5 AB x 1.5 AD

Area of rectangle A'B'C'D' = 1.5 x 1.5 ( ABxAD)

Area of rectangle A'B'C'D' = 2.25 x Area of rectangle ABCD

Thus, D is correct.  The area of A'B'C'D' is 2.25 times the area of ABCD.

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