If rectangular length and width difference 5,perimeter 110 then find length and width
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the length is 25 and width is 30
consider length =L
consider width =W
L-W =5.......(1)
2( L + W ) = 110
2L + 2W = 110......(2)
multiply eq(1)*2
2L - 2W =10........(3)
substraction from Eq(2) - (3)
L =25
put this value in eq (1) we get
W =30
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