Physics, asked by Nasir7864, 8 months ago

If relative density of gold is 19.3.The density is 10power3kg/mpower3. What is the density of gold in SI unit​

Answers

Answered by zahaansajid
1

Answer:

Density of gold = 19.3 × 10³ kg/m³

                          = 1.93 × 10⁴ kg /m³

                          = 19300 kg/m³

Explanation:

Given that,

Density of water = 10³

Relative density of gold = 19.3

We know that,

Relative density of gold = Density of gold / Density of water

Hence,

Density of gold = Relative density of gold × Density of water

Density of gold = 19.3 × 10³ kg/m³

                          = 1.93 × 10⁴ kg /m³

                          = 19300 kg/m³

Answered by Anonymous
1

Answer:

Density of a substance = relative density x density of water

Density of gold = 19.3 x 10³ = 19300 kg m³

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