Question

if remainder obtained by dividing 5x² +mx + 15 by (x-5) is 90 then find value of m​

Answer 1

Answer:

78

Step-by-step explanation:

The remainder obtained by dividing 5x² +mx + 15 by (x-5) is 90 the answer is 781-.23

Answer 2

SOLUTION

GIVEN

The remainder obtained by dividing 5x² + mx + 15 by ( x - 5 ) is 90

EVALUATION

Let

f(x) = 5x² + mx + 15

g(x) = x - 5

For Zero of the polynomial g(x) we have

g(x) = 0

⇒ x - 5 = 0

⇒ x = 5

So the remainder obtained by dividing 5x² + mx + 15 by ( x - 5 ) is

$\sf = f(5)$

$\sf = 5 \times {5}^{2} + (m \times 5) + 15$

$\sf = 125 + 5m + 15$

$\sf = 5m + 140$

So by the given condition

$\sf 5m + 140 = 90$

$\sf \implies \: 5m = - 50$

$\sf \implies \: m = - 10$

FINAL ANSWER

Hence the required value of m = - 10

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