Question

if remainder of (5m+1)(5m+3)(5m+4)/5 is a natural number then find it

Answer 1

Answer:

remainder = 2

Step-by-step explanation:

(5m+1)(5m+3)(5m+4)/5

Multiplying (5m+1)(5m+3) first

= (25m² + 15m +5m + 3)(5m + 4)/5

= (25m² + 20m + 3)(5m + 4)/5

Now multiplying 25m² + 20m + 3   with 5m+4

= 125m³ + 100m² + 100m² + 80m + 15m + 12)/5

(Splitting 12 into 2*5 + 2 = 10 + 2)

= (125m³ + 200m² + 95m + 10 + 2)/5

Taking 5 as common factor

= {5(25m³ + 40m² + 19m + 2) + 2}/5

= (25m³ + 40m² + 19m + 2)   + 2/5

remainder = 2

Answer 2

Answer:

here's ur answer in the pic