if resistance increases by 20percent find percentage change in current
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Answer:
Given,
Initial resistance R1=ρA1L1=10Ω
New length after stretch is L2=1.25L1
For constant volume
V=A1L1=A2L2
Hence,
A2A1=L1L2=1.2
⇒A2=1.2A1
Where,
V= Volume
A= Area
L=Length
New resistance of stretched wire,
R2=ρA2L2=ρA1/1.21
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