Question

If resistance
is made half and potential difference is made 4times calculate new current?

Answer 1

According to Ohm’s law V=IR

Hence when nothing changed [math]I_o=\dfrac{V}{R}[/math]

When potential difference is doubled and resistance is halved, then the current flowing is given by

[math]I'=\dfrac{V'}{R'}=\dfrac{2\times V}{\frac{R}{2}}=\dfrac{4V}{R}=4I_0[/math]

Hence current will become 4 times the original value.