if resistance of a wire of unit length is 26 ohm at 20 degree Celsius and its radius is 1.5 mm. find its resistivity
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Given,
Length of Wire, l = 1 m
(Note:- Unit of length is not mentioned in question, So We have taken as 1m)
Resistance, R = 26 ohm
Radius, r = 1.5 mm
r = 1.5 mm
r = 1.5 × 10⁻³ m
Area of cross section of wire = πr²
A = 3.14 × (1.5 × 10⁻³)²
A = 3.14 × 1.5 × 1.5 × 10⁻⁶
A = 7.065 × 10⁻⁶
We know that, Resistance of a wire at constant temperature is directly proportional its length and inversely proportional to its cross section area.
R ∝ l/A
R = ρl/A
Where ρ is Resistivity of wire.
ρ = RA/l
Putting values of R, A and l
ρ = (26×7.065 × 10⁻⁶)/1
ρ = 183.69 × 10⁻⁶
ρ = 1.83 × 10⁻⁴ Ω - m
ρ = 1.83 × 10⁻⁴ × 10⁻² Ω-cm
ρ = 1.83 × 10⁻⁶ Ω-cm
Length of Wire, l = 1 m
(Note:- Unit of length is not mentioned in question, So We have taken as 1m)
Resistance, R = 26 ohm
Radius, r = 1.5 mm
r = 1.5 mm
r = 1.5 × 10⁻³ m
Area of cross section of wire = πr²
A = 3.14 × (1.5 × 10⁻³)²
A = 3.14 × 1.5 × 1.5 × 10⁻⁶
A = 7.065 × 10⁻⁶
We know that, Resistance of a wire at constant temperature is directly proportional its length and inversely proportional to its cross section area.
R ∝ l/A
R = ρl/A
Where ρ is Resistivity of wire.
ρ = RA/l
Putting values of R, A and l
ρ = (26×7.065 × 10⁻⁶)/1
ρ = 183.69 × 10⁻⁶
ρ = 1.83 × 10⁻⁴ Ω - m
ρ = 1.83 × 10⁻⁴ × 10⁻² Ω-cm
ρ = 1.83 × 10⁻⁶ Ω-cm
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