Question

if resistance of two resistors are 6 plus minus 0.1 ohm and 3 + - 0.2 ohm then calculate their resistance in series and parallel combination of in error​

Answer 1

Rs=(R1+R2)±(ΔR+ΔR2)

Rs=9±0.3Ω

Rp=R1*R2/R1+R2±(ΔR1*ΔR2/ΔR1+ΔR2)

Rp=2±0.06Ω