If retardation produced by air resistance to the particle is one-tenth of acceleration due to gravity, the time to return from the maximum height:
(A) increases by 9%
(B) decreases by 9%
(C) increases by 11%
(D) decreases by 11%
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Answer:
(C)
Explanation:
t = u/g(effective)
t°=u/g [without air resistance]
t'=u/(g-g/10)
t'=10u/9g
.
t'/t°=10u * g/9g*u = 10/9
t'=10t°/9
∆t {t'-t°}= +11%
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