Question

If right angle triangle is given and it has base 45m and perpendicular distance 9 m than what is the value of third side

Answer 1

Answer:

45.891m

Step-by-step explanation:

According to Pythagoras Theorem :

${(perpendicular)}^{2} + {(base)}^{2} = {(hypotenuse)}^{2} \\ = > {9}^{2} + {45}^{2} = {(hypotenuse)}^{2} \\ = > 81 + 2025 = {(hypotenuse)}^{2} \\ = > 2,106 = {(hypotenuse)}^{2} \\ = > hypotenuse = \sqrt{2106} \\ = > hyptenuse = 45.891m$

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Answer 2

Answer:

Given:-

• Base = 45m
• Perpendicular distance = 9m

To Find:-

• The Third side (Hypotenuse)

Solution:-

According to Pythagoras theorem:-

${perpendicular \: distance}^{2} + {base}^{2} = {hypotenuse}^{2} \\ \\ \implies {45}^{2} + {9}^{2} = {hypotenuse}^{2} \\ \\ \implies \: 2025 + 81 = {hypotenuse}^{2} \\ \\ \implies \: hypotenuse = \sqrt{2106} \\ \\ = 45.8$