Question

If rocket-powered sled is accelerated to a speed of 400 m/s in 2 sec, then what is acceleration and what is the distance that the sled travels? ​

Answer 1

• initial velocity=u=0m/s
• Final velocity=v=400m/s
• Time=t=2s

We know

$\boxed{\sf Acceleration=\dfrac{v-u}{t}}$

$\\ \sf\longmapsto Acceleration=\dfrac{400-0}{2}$

$\\ \sf\longmapsto Acceleration=\dfrac{400}{2}$

$\\ \sf\longmapsto Acceleration=200m/s^2$

Now

Using second equation of kinematics

$\boxed{\sf s=ut+\dfrac{1}{2}at^2}$

$\\ \sf\longmapsto s=0(2)+\dfrac{1}{2}\times 200\times (2)^2$

$\\ \sf\longmapsto s=100\times 4$

$\\ \sf\longmapsto s=400m$